Which of the following species is the most stable?

H_{2} C = ∙ C H

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P h - ∙ C H_{2}

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(C H_{3})_{3} - ∙ C

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(C H_{3})_{2} - ∙ C H

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Solution

The correct option is B $P h - ∙ C H_{2}$
The stability of free radicals follows the order:
Benzyl Radical > $3^{\circ}$ radical > $2^{\circ}$ radical > $1^{\circ}$ radical.

Benzyl radical stabilised mostly by delocalisation in the ring through resonance.

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Similar questions

P h_{2} C = C H_{2}

C H_{3} - C \equiv C - C H_{3}

C H_{3} - C H = C H - C H_{3}

C H_{3} - C H_{2} C \equiv C H

C H_{3} - C H = C H_{2}

P h_{2} C = C H_{2}

C H_{3} - C H_{2} - C H_{2} - C H_{2} - B r

(C H_{3})_{2} - C H - C H_{2} - B r

(C H_{3})_{2} - C H - B r

C i s - P h ({C H}_{3}) C = C H P h

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