Question

Which of the following square planar complex does not show geometrical isomerism?

AA is symmetrical bidentate ligand
AB is unsymmetrical bidentate ligand
a and b are monodentate ligands

• A. $\left[M\right(AA)a_2{]}^{n\pm }$
• B. $[M{a}_{3}b{]}^{n\pm }$
• C. $\left[M\right(AB)a_2{]}^{n\pm }$
• D. $\left[M\right(AA)a_2{]}^{n\pm }$

Answer 1

Answer: (A), (B), (C), (D)

$\left[M\right(AA)a_2{]}^{n\pm }$

Square planar complex shows geometrical isomerism, cis and trans.
In all given complex, the geometrical isomerism is not possible because there is only one possible geometrical arrangement.