Question

Which of the following square planar complex is optically active?

• A. $\left[Pd\right(EDTA){]}^{2-}$ where EDTA act as tetradentate ligand​
• B. $\left[Pt\right(gly{)}_2]$​​
• C. Both (a) and (b)
• D. None of the above

Answer 1

The correct option is A $\left[Pd\right(EDTA){]}^{2-}$ where EDTA act as tetradentate ligand​

Square planar complexes generally do not show optical isomerism because all the 4 ligands and metal cations exist ​in the same plane and result in plane of symmetry.

In $\left[Pt\right(gly{)}_2]$, the bidentate ligand and​ metal are in same plane. Thus, it does not show optical isomerism.
Whereas in $\left[Pd\right(EDTA){]}^{2-}$, where EDTA act as tetradentate ligand​ , the compound doesn't show have plane of symmetry. Hence, it is optically active.

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