Which of the following statement does not hold true for the following reaction-xCu 3 P - yCr 2 O 72- zH - Cu 2- H 3 P O 4- Cr 3-A- Cu in Cu 3 P is oxidized to Cu 2- whereas P in Cu 3 P is also oxidized to P O 43-B- Cu in Cu 3 P is oxidized to Cu 2- whereas P in Cu 3 P is reduced to H 3 P O 4-C- In the conversion of Cu 3 P to Cu 2- and H 3 P O 4- 11 electrons are involved-D- The value of x is 6 -

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Which of the ...

Question

Which of the following statement does not hold true for the following reaction: $x C u_{3} P + y C r_{2} O_{7}^{2 -} + z H^{+} \to C u^{2 +} + H_{3} P O_{4} + C r^{3 +}$

Cu in

C u_{3} P

is oxidized to

C u^{2 +}

whereas P in

C u_{3} P

is also oxidized to

P O_{4}^{3 -}

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Cu in

C u_{3} P

is oxidized to

C u^{2 +}

whereas P in

C u_{3} P

is reduced to

H_{3} P O_{4}

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In the conversion of

C u_{3} P

C u^{2 +}

and

H_{3} P O_{4}

, 11 electrons are involved.

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The value of x is 6.

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Solution

The correct option is B Cu in $C u_{3} P$ is oxidized to $C u^{2 +}$ whereas P in $C u_{3} P$ is reduced to $H_{3} P O_{4}$ .
Oxidation state of P is getting changed from –3 to +5 during this conversion. That is, P in $C u_{3} P$ is getting oxidized to $H_{3} P O_{4}$ .

Suggest Corrections

Similar questions

Q. Balance the following equation by ion electron method.

C u_{3} P + C r_{2} O_{7}^{2 -} \to C u^{2 +} + H_{3} P O_{4} + C r^{3 +}

(acid medium).

Which of the following statement does not hold true for the following reaction?
$x C u_{3} P + y C r_{2} O_{7}^{2 -} + z H^{+} \to C u^{2 +} + H_{3} P O_{4} + C r^{3 +}$

Q. In the reaction

C u_{3} P + K_{2} C r_{2} O_{7} + H_{2} S O_{4} \to C u S O_{4} + H_{3} P O_{4} + C r_{2} (S O_{4})_{3} + H_{2} O

.
What is the n-factor of

C u_{3} P

Q. In the reaction

C u_{3} P + K_{2} C r_{2} O_{7} + H_{2} S O_{4} \to C u S O_{4} + H_{3} P O_{4} + C r_{2} (S O_{4})_{3} + H_{2} O

.
What is the n-factor of

C u_{3} P

Q. Which of the following statements is/are correct about the reaction?

H_{2} S O_{4} + C u_{3} P + C r_{2} O_{7}^{2 -} \to C u S O_{4} + H_{3} P O_{4} + 2 C r^{3 +}

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Which of the following statement does not hold true for the following reaction:xCu3P+yCr2O2−7+zH+→Cu2++H3PO4+Cr3+

The correct option is B Cu in Cu3P is oxidized to Cu2+ whereas P in Cu3P is reduced to H3PO4.Oxidation state of P is getting changed from –3 to +5 during this conversion. That is, P in Cu3P is getting oxidized to H3PO4.

Which of the following statement does not hold true for the following reaction: $x C u_{3} P + y C r_{2} O_{7}^{2 -} + z H^{+} \to C u^{2 +} + H_{3} P O_{4} + C r^{3 +}$

The correct option is B Cu in $C u_{3} P$ is oxidized to $C u^{2 +}$ whereas P in $C u_{3} P$ is reduced to $H_{3} P O_{4}$ .
Oxidation state of P is getting changed from –3 to +5 during this conversion. That is, P in $C u_{3} P$ is getting oxidized to $H_{3} P O_{4}$ .