Question

Which of the following statement is incorrect?

• A. During $N_2^{+}$ formation, one electron is removed from the bonding molecular orbital of $N_2$
• B. During $O_2^{+}$ formation, one electron is removed from the antibonding molecular orbital of $O_2$
• C. During $O_2^{-}$ formation, one electron is added to the bonding molecular orbital of $O_2$
• D. During $N_2^{-}$ formation, one electron is added to the antibonding molecular orbital of $N_2^{-}$

Answer 1

The correct option is C During $O_2^{-}$ formation, one electron is added to the bonding molecular orbital of $O_2$

$O_2:\left(\sigma 1s{)}^2\right({\sigma }^{\ast }1s{)}^2\left(\sigma 2s{)}^2\right({\sigma }^{\ast }2s{)}^2\left(\sigma 2p_z{)}^2\right(\pi 2p_x^2=\pi 2p_y^2\left)\right({\pi }^{\ast }2p_x^1={\pi }^{\ast }2p_y^1)$
During $O_2^{-}$ formation, 1 electron is added to the antibonding molecular orbital of $O_2$
$O_2^{-}:\left(\sigma 1s{)}^2\right({\sigma }^{\ast }1s{)}^2\left(\sigma 2s{)}^2\right({\sigma }^{\ast }2s{)}^2\left(\sigma 2p_z{)}^2\right(\pi 2p_x^2=\pi 2p_y^2\left)\right({\pi }^{\ast }2p_x^2={\pi }^{\ast }2p_y^1)$


$N_2$: $\left(\sigma 1s{)}^2\right({\sigma }^{\ast }1s{)}^2\left(\sigma 2s{)}^2\right({\sigma }^{\ast }2s{)}^2(\pi 2p_x^2=\pi 2p_y^2)(\sigma 2p_z{)}^2$
So, during formation of $N_2^{+}$, one electron is removed from the bonding molecular orbital

And during $N_2^{-}$ molecular orbital formation, one elctron is added to the antibonding molecular orbital.