Which of the following statement is incorrect for Solvay process:

N H_{3}

is reused

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C a C l_{2}

is one of final product

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N a_{2} C O_{3}

is partially changed into

N a H C O_{3}

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Potassium carbonate cannot be prepared by this method

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Solution

The correct option is C $N a_{2} C O_{3}$ is partially changed into $N a H C O_{3}$
Sodium carbonate is generally prepared by Solvay Process.
The equations for the complete process may be written as:
$2 N H_{3} + H_{2} O + C O_{2} \to (N H_{4})_{2} C O_{3} (N H_{4})_{2} C O_{3} + H_{2} O + C O_{2} \to 2 N H_{4} H C O_{3} N H_{4} H C O_{3} + N a C l \to N H_{4} C l + N a H C O_{3} 2 N a H C O_{3} Δ - \to N a_{2} C O_{3} + C O_{2} + H_{2} O$
In this process $N H_{3}$ is recovered when the solution containing $N H_{4} C l$ is treated with $C a (O H)_{2}$ . Calcium chloride is obtained as a by-product.
$2 N H_{4} C l + C a (O H)_{2} \to 2 N H_{3} + C a C l_{2} + H_{2} O$
Solvay process cannot be extended to the manufacture of potassium carbonate because potassium hydrogencarbonate is too soluble to be precipitated by the addition of ammonium hydrogencarbonate to a saturated solution of potassium chloride.

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