Question

Which of the following statement(s) is/are correct for an equimolar aqueous solution of $HCl$ and $N{H}_{4}OH$?

• A. $N{H}_4^{+}$ ions will undergo hydrolysis to form $N{H}_{4}OH$
• B. Solution will be basic in nature.
• C. Solution will be acidic in nature.
• D. Hydrolysis does not occur

Answer 1

Answer: (A), (C)

The correct options are
A $N{H}_4^{+}$ ions will undergo hydrolysis to form $N{H}_{4}OH$
C Solution will be acidic in nature.

Salt of a strong acid and a weak base $S.A+W.B.$
Consider strong acid $HCl$ and weak base $N{H}_{4}OH$ gives $N{H}_{4}Cl$ as a salt.
Complete dissociation :
$N{H}_{4}Cl⟶N{H}_4^{+}\left(aq\right)+C{l}^{-}\left(aq\right)$
Hydrolysis :
$N{H}_4^{+}\left(aq\right)+H_{2}O\left(l\right)\rightleftharpoons N{H}_{4}OH\left(aq\right)+H^{+}\left(aq\right)$
Note :-
Only the cation will undergo hydrolysis and the solution will be acidic in nature due to $H^{+}$ formation. So here, the cation is responsible for the acidic nature of the solution.
In this case $pH<7$.