Question

Which of the following statement(s) is/are correct?
i) Na reacts with liq. $N{H}_3$ to form paramagnetic species.
ii) $O_2$ reacts with 2-ethylanthraquinol form to paramagnetic species.
iii) Hydrolysis of 1 mol of peroxodisulphric acid produces 1 mol of sulphuric acid and 2 mole of peroxomono sulphuric acid.

• A. i
• B. ii
• C. i and ii
• D. i and iii

Answer 1

Answer: (A)

i

i) $Na$ reacts with liq. $N{H}_3$ to form paramagnetic species.
$Na$ dissolves in liq.$N{H}_3$ to form ammoniated metal cation and ammoniated electrons. Ammoniated electrons are paramagnetic species.
$Na+(x+y)N{H}_3\to \left[Na\right(N{H}_3{)}_x{]}^{+}+\left[e^{-}\right(N{H}_3{)}_y{]}^{-}$

ii) $O_2$ reacts with 2-ethylanthraquinol to form diamagnetic species.

iii) Hydrolysis of 1 mol of peroxodisulphroic acid produces 1 mol of sulphuric acid and 1 mole of peroxomono sulphuric acid.