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Question

Which of the following statement(s) is/are correct regarding the given electrode potential data?
Fe3+(aq) + eFe2+(aq); E0=+0.77 V
Al3+(aq) + 3eAl(s); E0=1.66 V
Br2(g) + 2e2Br(aq); E0=+1.08 V

A
Fe2+ is stronger reducing agent than Br
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B
Fe2+ is stronger reducing agent than Al
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C
Al is stronger reducing agent than Fe2+
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D
Br is stronger reducing agent than Al
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Solution

The correct option is C Al is stronger reducing agent than Fe2+
Standard reduction potentials (SRP) of the half cell electrodes are calculated and arranged in a series of increasing order which is known as electrochemical series.
The standard electrode potential of H+/H2 couple is zero.

Here, a negative E0 signifies that it has high tendency to get oxidised and the redox couple is a stronger reducing agent than the H+/H2 couple.

A positive E0 signifies that it has high tendency to get reduced and the redox couple is a stronger oxidising agent than the H+/H2 couple.

Going down the electrochemical series, the E0 value decrease i.e., the strength of oxidising agent gets reduced.

From the given potential data,
Br2/Br couple has the highest E0value so it is the strongest oxidising agent than Fe3+ and Al3+

Fe3+/Fe2+ couple has lower E0 value than Br2/Br couple so Fe2+ is a stronger reducing agent than Br

Fe3+/Fe2+ couple has higher E0 value than Al3+/Al couple so Fe3+ is stronger oxidising agent than Al3+ and Al is the stronger reducing agent than Fe2+

Thus, statement (a) and (c) are correct.

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