Which of the following statement(s) is/are correct when a mixture of $N a C l$ and $K_{2} C r_{2} O_{7}$ is gently warned with conc. $H_{2} S O_{4}$ ?

A deep red vapour is evolved

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The vapours when passed into

N a O H

solution gives a yellow solution of

N a_{2} C r O_{4}

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Chlorine gas is evolved

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Chromyl chloride is formed

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Solution

The correct option is D Chromyl chloride is formed
$C l^{-}$ ion is confirmed by chromyl chloride test.
Chromyl chloride is produced as deep red vapour when a chloride ion reacts with conc. $H_{2} S O_{4} and K_{2} C r_{2} O_{7}$ .
Passing the chromyl chloride gas through $N a O H$ turns the solution yellow. This is due to the formation of $N a_{2} C r O_{4}$ .
The reactions are,
$4 N a C l + K_{2} C r_{2} O_{7} + 6 H_{2} S O_{4} \to 2 C r O_{2} C l_{2} C h r o m y l c h l o r i d e + 4 N a H S O_{4} + 2 K H S O_{4} + 3 H_{2} O$

$2 C r O_{2} C l_{2} + 4 N a O H \to N a_{2} C r O_{4} S o d i u m c h r o m a t e (y e l l o w s o l u t i o n) + 2 N a C l + 2 H_{2} O$

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Which of the following statement(s) is/are correct when a mixture of $N a C l$ and $K_{2} C r_{2} O_{7}$ are gently warmed with conc. $H_{2} S O_{4}$ ?

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Which of the following statement(s) is/are correct when a mixture of $N a C l$ and $K_{2} C r_{2} O_{7}$ are gently warmed with conc. $H_{2} S O_{4}$ ?

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Which of the following statement(s) is/are correct when a mixture of $N a C l$ and $K_{2} C r_{2} O_{7}$ is gently warned with conc. $H_{2} S O_{4}$ ?