Which of the following statement(s) is (are) correct when a mixture of $N a C l$ and $K_{2} C r_{2} O_{7}$ is gently warmed with conc. $H_{2} S O_{4}$ ?

A deep red vapour is evolved

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The vapour when passed through

N a O H

solution, gives a yellow solution

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Chlorine gas is also evolved

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Chromyl chloride is formed

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Solution

The correct options are
A A deep red vapour is evolved
B The vapour when passed through $N a O H$ solution, gives a yellow solution
D Chromyl chloride is formed
When a mixture of NaCl and $K_{2} C r_{2} O_{7}$ is gently warmed with conc. $H_{2} S O_{4}$ .
(A) A deep red vapour (of chromyl chloride) is evolved.
(B) The vapour when passed through NaOH solution, gives a yellow solution, ude to formation of sodium chromate .
(C) Chlorine gas is not evolved but NaCl is formed.
(D) Chromyl chloride $(C r O_{2} C l_{2})$ is formed.
$K_{2} C r_{2} O_{7} + 6 H_{2} S O_{4} + 4 N a C l \to 2 K H S O_{4} + 4 N a H S O_{4} + 2 C r O_{2} C l_{2} + 3 H_{2} O (c h r o m y l c h l o r i d e) (O r a n g e R e d - V a p o u r)$
$4 N a O H + C r O_{2} C l_{2} \to N a_{2} C r O_{4} + 2 N a C l + 2 H_{2} O (y e l l o w s o l u t i o n)$

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