Question

Which of the following statements about the following reaction is/are wrong?
$2{Cu}_{2}O\left(s\right)+{Cu}_{2}S\left(s\right)⟶6Cu\left(s\right)+5O_2\left(g\right)$

• A. Both ${Cu}_{2}O$ and ${Cu}_{2}S$ are reduced.
• B. Only ${Cu}_{2}S$ is reduced.
• C. ${Cu}_{2}S$ is the oxidant.
• D. Only ${Cu}_{2}O$ is reduced.

Answer 1

Answer: (B), (D)

The correct options are
B Only ${Cu}_{2}O$ is reduced.
D Only ${Cu}_{2}S$ is reduced.

Copper in $C{u}_{2}O$ is reduced as its oxidation number decreases from +1 to 0.
Copper in $C{u}_{2}S$ is reduced as its oxidation number decreases from +1 to 0.
Thus, both $C{u}_{2}O$ and $C{u}_{2}S$ are reduced.