Which of the following statements about the reaction is/are correct?
$H g S + H C l + H N O_{3} ⟶ H_{2} H g {C l}_{4} + N O + S + H_{2} O$

H g

is reduced.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Sulphide is oxidised.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N

is reduced.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H N O_{3}

is oxidant.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
B Sulphide is oxidised.
C $N$ is reduced.
D $H N O_{3}$ is oxidant.
$H g S + H C l + H N O_{3} ⟶ H_{2} H g {C l}_{4} + N O + S + H_{2} O$
+2 -2 +1 +5 +2 +2 0

$S^{2 -} ⟶ S + 2 e^{-}$ (Oxidised)

$3 e^{-} + N O_{3}^{⊖} ⟶ N O$

Here, we can see that $S^{2 -}$ is oxidised while $H N O_{3}$ is reduced.

So, $H N O_{3}$ acts as an oxidising agent.

Hence, options $B, C, a n d D$ are correct.

Suggest Corrections

Similar questions

H g S + H C l + H N O_{3} \to H_{2} [H g C l_{4}] + N O + S + H_{2} O

H g S + H I + H N O_{3} \to H_{2} H g I_{4} + N O + S + H_{2} O

A c O H^{\oplus}

H g^{+}

H g^{\circ}

H g^{2 +}

H g^{+}

H g^{2 +}

H g^{\circ}

H N O_{3} + H C l \to N O + C l_{2} + H_{2} O

H N O_{3}

F e^{2 +}

(H N O_{3} + F e^{2 +} \to F e^{3 +} + N O + H_{2} O)

Join BYJU'S Learning Program