Question

Which of the following statements are correct about the reaction between the copper metal and dilute $HN{O}_3$ ?

I) The principle reducing product is NO gas.

II) Cu metal is oxidized to $C{u}^{2+}$(a q.) ion which is blue in colour.

III) NO is para magnetic and has one unpaired electron in antibonding molecular orbital.

IV) NO reacts with $O_2$ to produce $N{O}_2$ which is linear in shape.

• A. I, II, III
• B. I, III
• C. II, IV
• D. All of the above

Answer 1

Answer: (A)

I, II, III

Reaction is:
$3Cu+8HN{O}_3\to 3Cu(N{O}_3{)}_2+2NO+4H_{2}O$
Also,
NO is para magnetic and has one unpaired electron in antibonding molecular orbital as shown above.