Question

Which of the following statements are correct for an X-ray tube?

• A. On increasing potential difference between the filament and target, photon flux of X-rays increases
• B. On increasing potential difference between the filament and target, frequency of X-rays increases
• C. On increasing filament current, cut-off wavelength increases
• D. On increasing filament current, intensity of X-rays increases

Answer 1

Answer: (B), (D)

The correct options are
B On increasing potential difference between the filament and target, frequency of X-rays increases
D On increasing filament current, intensity of X-rays increases

$h\nu =W_0+\frac{1}{2}m{V}_{max}^2$

$W_0=\mid e{V}_s\mid$

$V_s=\frac{m{V}^2}{2e}$

So,
$K{E}_e\propto V$
$frequency\propto KE$
Hence $frequency\propto V$
$Current=Ne/t$
more is the current,more the no. of electrons accelerated and more the atoms bombarded, and hence more the X-rays emitted.