(i) Boron reacts with concentrated HNO3 to form nitric oxide and boric acid (ii) Boron reacts with fused NaOH to form H2O2 and boric acid (iii) Boron reacts with SiO2 to form Si and B2O3
A
(i), (ii) and (iii)
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B
(i) and (iii)
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C
(ii) and (iii)
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D
(i) and (ii)
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Solution
The correct option is B (i) and (iii) (i) Boron reacts with concentrated HNO3 to form nitric oxide and boric acid.B+HNO3+H2O→H3BO3+NO
(ii) Boron reacts with fused Sodium Hydroxide to form Sodium Borate and Hydrogen.
B+6NaOH→2Na3BO3+3H2
(iii) Boron reacts with SiO2 to form Si and B2O3. 4B+3SiO2→3Si+2B2O3