Which of the following statements are correct regarding metallurgy of iron?

Coke reduces

F e O

F e

above 710

^{\circ}

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CO reduces

F e_{2} O_{3}

F e

below 710

^{\circ}

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Coke reduces

F e_{2} O_{3}

F e O

below 710

^{\circ}

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CO reduces

F e_{2} O_{3}

F e O

above 710

^{\circ}

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Solution

The correct options are
B Coke reduces $F e O$ to $F e$ above 710 $^{\circ}$ C
C CO reduces $F e_{2} O_{3}$ to $F e$ below 710 $^{\circ}$ C
Coke reduces $F e O$ to $F e$ above 710 $^{\circ} C$ .
$F e O + C \to F e + C O$

In the blast furnace, it is so hot that carbon monoxide can be used to reduce the iron oxide in place of carbon at below 710 $^{\circ} C$ .

$F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}$

Hence options A & B are correct.

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Similar questions

Q. Assertion :Reduction of

F e_{2} O_{3}

, with CO is done below 710

^{\circ}

C. Reason:

Δ

G is negative at this temperature; thus,process is spontaneous.

Read the above assertion and reason and choose the correct option regarding it.

You are given an Ellingham diagram (deliberately not shown). It is given that for almost all practically achievable temperatures, the $F e \to F e_{2} O_{3}$ line lies above the $A l \to A l_{2} O_{3}$ line and $Δ_{f} G^{\circ}$ for both $A l_{2} O_{3}$ and $F e_{2} O_{3}$ are negative. Which of the following statements is/are true?