Which of the following statements are correct with reference to the ferrous and ferric ions?

F e^{3 +}

gives brown colour with potassium ferricyanide

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F e^{2 +}

gives Turnbull's blue precipitate with potassium ferricyanide

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F e^{3 +}

gives blood red colour with potassium thiocyanate

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F e^{2 +}

gives brown colour with ammonium thiocyanate

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Solution

The correct option is C $F e^{3 +}$ gives blood red colour with potassium thiocyanate
The blue precipitate of $F e^{2 +}$ ion with potassium ferricyanide is due to the formation of Turnbull's blue complex $F e_{3} [F e (C N)_{6}]_{2}$ .

$3 F e^{2 +} + 2 K_{3} [F e (C N)_{6}] ⟶ F e_{3} [F e (C N)_{6}]_{2} + 6 K^{+}$

The blood red colour of $F e^{3 +}$ ion with potassium thiocyanate is due to formation of $[F e (S C N)_{3}]$ complex.

$F e^{3 +} + 3 K S C N ⟶ [F e (S C N)_{3}] + 3 K^{+}$

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