Question

Which of the following statements is/are correct about $6.8\%$ strength of $H_2{O}_2$?

• A. Its normality is $4N$
• B. Its molarity is $2M$
• C. Its volume strength is $22.4V$
• D. Volume strength $=11.2\times M$

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A Its normality is $4N$
B Its molarity is $2M$
C Its volume strength is $22.4V$
D Volume strength $=11.2\times M$

Given,
$6.8g$ in $100mL$ solution
$\therefore$ $68g$ in $1000mL$ solution
Molarity of the solution= $\frac{\frac{68}{34}mol}{1L}=2M$
So normality will be $=2\times 2=4N$

Again,
$H_2{O}_2=H_{2}O+\frac{1}{2}{O}_2$

We know, volume strength refers to the volume of oxygen gas liberated from 1 volume of $H_2{O}_2$.
Since 1 mol of $H_2{O}_2$ gives $\frac{1}{2}molof{O}_2$
Thus volume strength $=\frac{22.4}{2}\times M=11.2\times M$

So here volume strength of the solution is $11.2\times 2=22.4V$