The correct options are
A Its normality is 4 N.
B Its volume strength is 11.2 M.
C Its volume strength is 22.4 V.
D Its molarity is 2 M.
a. 1.7%=1N
6.8%=4N
b. M=4N2=2M
c. 1.7%=5.6′V′
6.8%=22.4′V′
d. Volume strength =5.6×N=5.6×2×M=11.2×M
Hence options A,B,C & D are correct.