I: Every function must be either even or odd function II: The function f(x)=log(x+√x2+1) is an odd function.
A
Only I is true
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B
Only II is true
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C
Both I and II are true
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D
Neither I nor II is true
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Solution
The correct option is B Only II is true I A function can be odd, even or neither odd nor even. II f(x)=log(x+√x2+1) f(−x)=log(√x2+1−x) f(−x)=log((√x2+1−x)×√x2+1+x√x2+1+x) =log(1√x2+1+x) =−log(x+√x2+1) f(−x)=−f(x) ∴f(x) is an odd function