Question

Which of the following statements is correct regarding the structure of $PC{l}_5$?

• A. Three $P-Cl$ bonds lie in one plane and two $P-Cl$ bonds lie above and below the equatorial plane.
• B. Five $P-Cl$ bonds lie in the same plane.
• C. The bond angle in all $P-Cl$ bonds is ${90}^o$.
• D. The bond length of all $P-Cl$ bonds is same.

Answer 1

The correct option is A Three $P-Cl$ bonds lie in one plane and two $P-Cl$ bonds lie above and below the equatorial plane.

The molecule of $PC{l}_5$ has $5$ bond pairs and zero lone pairs.

That's why the shape is trigonal pyramidal and it shows $s{p}^{3}d$ hybridization.

In the case of trigonal pyramidal, $3$ bonds retain in one plane and rest $2$ bonds retain in another plane.

The bond angle is ${90}^o$ only for a bond in an axial plane.

so the correct option is [A]