Question

Which of the following statements is correct wrt the following graph?

• A. Below $1623K,Mg$ reduces $A{l}_2{O}_3$ to Al
• B. Above $1623K,Al$ reduces $MgO$ to Mg
• C. Both (a) and (b) are correct
• D.
  Both (a) and (b) are wrong

Answer 1

The correct option is C Both (a) and (b) are correct

Any metal will reduce the oxide of other metal which lie above it in Ellingham diagram.
Hence, $1623K,Mg$ reduces $A{l}_2{O}_3$ to Al and above $1623K,Al$ reduces $MgO$ to Mg.