Which of the following statements is incorrect

For drawing a histogram of a continuous grouped frequency distribution with unequal class intervals, you have to compute the adjusted frequencies of each class

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The formula for computing the adjusted frequencies is {Maximum class size /class mark} x frequency of the class

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For a given frequency distribution, a frequency polygon can be drawn without using a histogram

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To construct a histogram, you have to construct rectangles with class intervals as bases and respective frequencies as heights

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Solution

The correct option is B
The formula for computing the adjusted frequencies is {Maximum class size /class mark} x frequency of the class

Adjusted frequency = {minimum class size/class interval} ´ frequency of that class

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Similar questions

Q. Now, we construct rectangles with class-limits as bases and respective adjusted frequencies as heights. Draw a histogram for the marks of students given below:

Q. Construct the histogram for the following grouped frequency distribution.

Class intervals	Frequency
0-35	42
35-50	30
50-60	20
60-100	48

Q. In a histogram, each class rectangle is constructed with base as

(a) frequency

(b) class-intervals

(c) range

(d) size of the class

The frequency polygon of a frequency distribution is shown below.

Answer the following about the distribution from the histogram.

(i) What is the frequency of the class interval whose class mark is 15?

(ii) What is the class interval whose class mark is 45?

(iii) Construct a frequency table for the distribution.

Q. Construct the histogram for the following grouped frequency distribution.

Class intervals	Frequency
0 - 35	70
35 - 50	15
50 - 60	20
60 - 100	40

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Which of the following statements is incorrect

The correct option is B The formula for computing the adjusted frequencies is {Maximum class size /class mark} x frequency of the class Adjusted frequency = {minimum class size/class interval} ´ frequency of that class

The correct option is B
The formula for computing the adjusted frequencies is {Maximum class size /class mark} x frequency of the class

Adjusted frequency = {minimum class size/class interval} ´ frequency of that class