Which of the following statements regarding, 1,2-dimethyl cyclopropane (I) and 1,2-dimethyl cyclobutane (II) are wrong?

Both of them show three stereoisomers.

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The cis form of both is optically inactive(meso) and the trans form of both has a pair of enantiomers.

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The cis form of both has a pair enantiomers and the trans form of both is optically inactive (meso).

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The meso form of both is optically inactive due to the presence of the centre of symmetry.

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Solution

The correct options are
C The meso form of both is optically inactive due to the presence of the centre of symmetry.
D The cis form of both has a pair enantiomers and the trans form of both is optically inactive (meso).
The statements A and B are correct and the statements C and D are wrong.
(A) Both $1, 2 - d i m e t h y l$ cyclopropane (I) and $1, 2 - d i m e t h y l c y c l o b u t a n e$ (II) show three stereoisomers.
(B) The cis form of both is optically inactive (meso) and the trans form of both has a pair of enantiomers.

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