Which of the following structures will show geometrical isomerism?

{C H}_{3} C H {= C C I}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C H}_{3} - C C I = C B r - {C H}_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{C H}_{3} C H = C H B r

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P h - C H = N - O H

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A $P h - C H = N - O H$
C ${C H}_{3} - C C I = C B r - {C H}_{3}$
D ${C H}_{3} C H = C H B r$
For geometrical isomerism, the double bond must have :
(1) Restricted rotation
(2) Same plane
(3) Different Groups.
Thus, $C H_{3} - C C I = C B r - C H_{3}, C H_{3} C H = C H B r$ and, $P h - C H = N - O H$ Show Geometrical isomers

Suggest Corrections

Similar questions

{C H}_{3} C H (B r) {C H}_{2} {C H}_{3} A l c . K O H - ----- \to

{C H}_{3} C H = C H - {C H}_{3}

{C H}_{2} = C H {C H}_{2} {C H}_{3}

C H_{3} C H_{2} - C H_{2} - O H

C H_{3} C H_{2} - (C H_{3}) C H - O H

C H_{3} C H_{2} - C H_{3} | C | C H_{3} - O H

C H_{3} C H = C H C H_{3} (i i) B - -- \to (i) A C H_{3} - C | H O H - O H | C H - C H_{3}

A & B

C h_{3} C = C - C H_{3}

C H_{3} C H_{2} - C H_{2} - C H_{3}

C H_{3} C H_{2} C = C H

C H_{3} C H = C H_{2}

Join BYJU'S Learning Program