The correct option is D NaNO2
NaNO2 (Sodium nitrite) act both as oxidising as well as reducing agent because in it N atom is in +3 oxidation state (intermediate oxidation state) Oxidising property
2NaNO2+2KI+2H2SO4→Na2SO4+K2SO4+2NO+2H2O+I2
Reducing property
H2O2+NaNO2→NaNO3+H2O.