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Question

Which of the following terms in the expression 5y211y+2yz5z have "y" as a common factor?

A
2yz,5z,5y2
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B
5y2,11y,2yz
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C
2yz,5z
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D
5y2,5z
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Solution

The correct option is B 5y2,11y,2yz
5y2=5×y×y
11y=11×y
2yz=2×y×z
5z=5×z

5y2,11y and 2yz have y as a common factor.

So, option B is correct.

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