The correct option is A I2/NaOH
2- pentanone is a methyl ketone. It undergoes haloform reaction with iodine in presence of sodium hydroxide, to form yellow precipitate of iodoform. 3- pentanone is not a methyl ketone. It does not undergo haloform reaction. Hence, 3- pentanone and 2- pentanone can be distinguished by reaction with iodine in presence of NaOH.