Which of the following thermodynamic relation is correct?

d G = V d p - S d T

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d E = p d V + T d S

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d H = - V d p + T d S

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d G = V d p + S d T

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Solution

The correct option is C $d G = V d p - S d T$

$d G = d H - T d S - S d T$ (as $G = H - T S)$
Again, $H = E + p V$
$∴ d H = d E + p d V + V d p$
and $d E = T d s - p d V$
Thus, $d G = (T d S - p d V) + p d V + V d p - T d S - S d T = V d p - S d T$

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Similar questions

d E = T d S - p d V

H = E + p V

In the given figure if $∠ G H E = ∠ D F E = 90^{\circ}$ , DH = 8 cm, DF = 12 cm, DG = 3x - 1 and DE = 4x + 2, then DG and DE are respectively ___.

Given: $∠ G H E = ∠ D F E = 90^{\circ}$ (IMAGE)

$D H = 8, D F = 12, D G = 3 x - 1$ and $D E = 4 x + 2.$ Find the
lengths of segments $D G$ and $D E$ .

γ = \frac{C_{P}}{C_{V}}

\frac{4}{3}

d U = n (V d P + P d V)

n

∠ G H E = ∠ D F E = 90^{\circ}, D H = 8 c m, D F = 12 c m, D G = (3 x - 1) c m

D E = (4 x + 2) c m

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