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Question

Which of the following transformations can be carried out by using HI as a reducing agent, under acidic conditions?
[Given:I2(s)2IE=0.54V]
(i)Cu+Cu E=0.52V(ii)Cr3+Cr2+ E= 0.41V(iii)Fe3+Fe2+ E=0.77V(iv)Fe2+Fe E= 0.44V

A
(i) and (iii)
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B
(ii) and (iv)
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C
only (iii)
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D
only (ii)
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Solution

The correct option is C only (iii)
Here only (iii) E value is more than 0.54V so HI can be used to reduce Fe3+

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