Which of the following transition corresponds to the second line in Balmer series?
A
2 → 1
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B
3 → 2
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C
4 → 2
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D
3 → 1
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Solution
The correct option is C 4 → 2 Balmer series emerges from the electronic transmission from higher level down to the n = 2 i.e., transitions where n1=2 and n2=3,4,5,...... So, first line in Balmer series is 3→2 and second line is 4→2.