The correct option is A Zn
Outer electronic configuration of Zn= 3d10 4s2.
Outer electronic configuration of Sc= 3d1 4s2.
Outer electronic configuration of Co= 3d7 4s2.
Outer electronic configuration of Mn= 3d5 4s2.
In general, the greater the number of unpaired electrons, the stronger is the resultant bonding and hence, higher is the enthalpy of atomisation. In the 3d series, from Sc to Zn, Zn has no unpaired electrons. Hence, it exhibits weak interactions and thus possesses the least enthalpy of atomisation.