Question

Which of the following transitions in the hydrogen atom emit the photon of highest frequency?

• A. $n=2$ to $n=6$
• B. $n=6$ to $n=2$
• C. $n=1$ to $n=2$
• D. $n=2$ to $n=1$

Answer 1

The correct option is D $n=2$ to $n=1$

$\begin{array}{c}\text{we know that the energy of a photon is given by-}\\ \begin{array}{c}h\nu =-13.6\left[\frac{1}{n_1^2}\frac{1}{n_2^2}\right]\text{where}v=\text{frequency}\\ \text{from}n=2\text{to}n=1\\ \text{we get,}v=\frac{1}{h}[13.6\times \frac{3}{4}]=\frac{10.2}{h}{\text{sec}}^{-1}\\ \text{which is maximum among others.}\end{array}\end{array}$