Question

Which of the following transitions of an electron in a H-atom would emit a photon of minimum wavelength?

• A. $8$ to $3$
• B. $6$ to $1$
• C. $2$ to $1$
• D. $7$ to $5$

Answer 1

Answer: (B)

$6$ to $1$

We know that $\frac{1}{\lambda }=R(\frac{1}{n_1^2}-\frac{1}{n_2^2})$

Hence more the difference of square of orbits , lower the wavelength of photon.

Here $\frac{1}{\lambda }=R(\frac{1}{1^2}-\frac{1}{6^2})$

$\frac{1}{\lambda }=R\left(\frac{36-1}{\left(36\right)\left(1\right)}\right)$

Hence this transition has the minimum wavelength.