Which of the following turns lead acetate paper black?

S O_{2}

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S O_{3}

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H_{2} S

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H_{2} S O_{4}

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Solution

The correct option is A $H_{2} S$
$P b (C H_{3} C O O)_{2} (l e a d a c e t a t e) + H_{2} S \to P b S (b l a c k) ↓ + A c e t i c A c i d$
formation of black ppt in $P b S$

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H_{2} S O_{4}

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