Question

Which of the following type of plot would you expect from the titration of $AgN{O}_3$ againest $KCl$ solution ?

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

When $AgN{O}_3$ is titrated against KCl following reaction occurs,
$A{g}^{+}N{O}_3^{-}+K^{+}C{l}^{-}\to AgCl\left(s\right)\downarrow +K^{+}N{O}_3^{-}$
Here $AgCl$ precipitates out. For each mole of $C{l}^{-}$ displaced from solution, $1$ mole of $N{O}_3^{-}$ comes in solution resulting in almost contstant conductivity.

At the end point, the added $AgN{O}_3$ remains in solution increasing ionic concentration, therefore conductivity rapidly increases.