Which of the following types of carbon atoms possess the highest electronegativity?

s p^{3}

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s p^{2}

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s p

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All have equal electronegativity

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Solution

The correct option is C $s p$
Electronegativity $\propto$ %s-character
$s p^{3} = 25 %, s p^{2} = 33.33 %, s p = 50 %$

Hence, option C is correct.

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Similar questions

s p, s p^{2}

s p^{3}

State whether true or false
The correct order regarding the electronegativity of hybrid orbitals of carbon is
sp > ${s p}^{2}$ > ${s p}^{3}$

s p^{3}

s p^{3}

(C_{3} H_{4})

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