Which of the following value of $x$ satisfies the equation $25 x^{2} - 30 x + 9 = 0$ ?

- \frac{3}{5}

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\frac{5}{3}

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\frac{3}{5}

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\frac{2}{5}

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Solution

The correct option is D $\frac{3}{5}$
$25 x^{2} - 30 x + 9 = 0$
$\Rightarrow {(5 x)}^{2} - 2 (5 x) \times 3 + {(3)}^{2} = 0$
$\Rightarrow {(5 x - 3)}^{2} = 0$
This gives x = $\frac{3}{5}, \frac{3}{5}$ or simply x = $\frac{3}{5}$ as the required solution

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