You visited us 1 times! Enjoying our articles? Unlock Full Access!

Solving Inequalities

Which of the ...

Question

Which of the following values of x do not satisfy the inequality $x^{2} - 3 x + 2 > 0$ at all?

1 \leq x \leq 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 < x < 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 5 \leq x \leq - 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 < x \leq 10

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $1 \leq x \leq 2$
Given inequality is $x^{2} - 3 x + 2 > 0$
$\Rightarrow x^{2} - 2 x - x + 2 > 0 \Rightarrow x (x - 2) - 1 (x - 2) > 0 \Rightarrow (x - 2) (x - 1) > 0 \Rightarrow x < 1, x > 2$

Suggest Corrections

Similar questions

x^{2} - 3 x + 2 > 0

x^{2} - 3 x - 4 \leq 0

[m, n) (p, q]

m + n + p + q

x

\frac{x^{2} - 3 x + 4}{x^{2} - 6 x + 8} \leq 0

x

x^{2} - 3 x + 2 > 0

x^{2} - 3 x - 4 \leq 0

m

\frac{x^{2} - m x - 2}{x^{2} - 3 x + 4} > - 1

x ϵ R ?

x^{2} - 3 x + 2 > 0

x^{2} - 3 x - 4 \leq 0

Join BYJU'S Learning Program