Which of the following vectors is perpendicular to the vector $4^i - 3^j$ ?

4^i + 3^j

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6^i

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7^k

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3^i + 4^j

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $3^i + 4^j$
$L e t$ $v e c t o r$ $u = (a i + b j)$ $i s$ $p e r p e n d i c u l a r$ $t o$ $v e c t o r$ $v = (4 i - 3 j)$

$T h a t$ $m e a n s$ $D o t$ $p r o d u c t$ $o f$ $u . v$ $i s$ $e q u a l$ $t o$ $z e r o .$

$u . v = 0$

$u . v = (a i + b j) . (4 i - 3 j) = 0$

$(4 a - 3 b) = 0$

$4 a = 3 b$

$\frac{a}{b} = \frac{3}{4}$

$a = 3$ $a n d$ $b = 4$

$P e r p e n d i c u l a r$ $v e c t o r$ $i s$ $u = (3 i + 4 j)$

Suggest Corrections

Similar questions

\to F = 4^i - 3^j

\to F

\to A = 4^i + 3^j

\to B = 3^i - 4^j

\to A = 4^i + 3^j

\to B = 3^i + 4^j

^i - 3^j + 2^k

3^i + 6^j - 7^k

1 kg

_{1} = (^i + 2^j + 7^k),_{2} = (3^i + 5^j +^k),

_{3} = (6^i + 2^j + 3^k)

_{4} = (2^i -^j + 5^k)

Join BYJU'S Learning Program