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Nucleophilic Substitution in Alkyl Halides

Which of the ...

Question

Which of the following when treated with aniline will give benzene diazonium chloride as the major product?

{N a N O}_{2}

and

H C l

between

0 - 5^{0} C

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{H N O}_{3}

and

H C l

between

0 - 5^{0} C

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C_{6} H_{5} {N O}_{2}

between

0 - 5^{0} C

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{N a N O}_{2}

between

0 - 5^{0} C

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Solution

The correct option is A ${N a N O}_{2}$ and $H C l$ between $0 - 5^{0} C$
Benzene diazonium chloride is $P h N_{2}^{+} C l^{-}$ .

It is formed when aniline is treated with $N a N O_{2} - H C l$ at a temperature between 0-5 $^{\circ} C$ .

$P h N H_{2} + N a N O_{2} + H C l \to P h N_{2}^{+} C l^{-}$

Benzene diazonium chloride is an important synthetic intermediate and is used in a number of reactions.

Option A is correct.

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Similar questions

N a N O_{2}

H C l

0 - 5^{0} C

{0 - 5}^{0} C

{N a N O}_{2}

N a N O_{2}

H C l

^{\circ} C

When Aniline is treated with Nitrous acid, which is prepared

in situ

from Sodium Nitrite and mineral acid, the product formed is:

$C_{6} H_{5} N H_{2} + H C l + N a N O_{2} \to$ _____________ + $2 H_{2} O$

A

(C_{7} H_{9} N)

N a N O_{2} / H C l

0 - 5^{0} C

A

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