Which of the following will accept $H^{+} from N H_{4}^{+}$ ion?

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C H_{3} - C H_{2} - N H_{2}

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Solution

The correct option is D
$C H_{3} - C H_{2} - N H_{2}$
The aniline and pyrrole are less basic than aliphatic amines because lone pair of nitrogen in aromatic amines are involved in resonance so it can't accept $H^{+} from N H_{4}^{+}$ ion.
Ethanamine has localised lone pair electron on N thus it can accept $H^{+} from N H_{4}^{+}$ ion. Hence option d is correct.

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