Which of the following will be the most effective in the coagulation of $F e (O H)_{3}$ sol?

M g_{3} (P O_{4})_{2}

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B a C l_{2}

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NaCl

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KCN

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Solution

The correct option is A $M g_{3} (P O_{4})_{2}$
$F e (O H)_{3}$ sol is positively charged sol. It will be coagulated by negatively charged ions.
$M g_{3} (P O_{4})_{2}$ provides phosphate ions $P O_{4}^{3 -}$ which have maximum negative charge among the given electrolytes.

Hence, $M g_{3} (P O_{4})_{2}$ will be the most effective in the coagulation of $F e (O H)_{3}$ sol.

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