Which of the following will exhibit maximum ionic conductivity?

K_{4} [F e {(C N)}_{6}]

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[C o {(N H_{3})}_{6}] C l_{3}

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[C u {(N H_{3})}_{4}] C l_{2}

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[N i {(C O)}_{4}]

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Solution

The correct option is A $K_{4} [F e {(C N)}_{6}]$
The number of ions produced upon hydrolysis by each of these coordination compounds are as follows:

$[C o {(N H_{3})}_{6}] C l_{3}$ produces 4 ions, $K_{4} [F e {(C N)}_{6}]$ produces 5 ions, $[C u {(N H_{3})}_{4}] C l_{2}$ produces 3 ions and $[N i {(C O)}_{4}]$ does not produce any ion.

So, $K_{4} [F e {(C N)}_{6}]$ gives maximum number of ions in solution. Hence, its ionic conductivity will be the highest.

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Similar questions

Q. Write IUPAC names of the following coordination compounds.
a)

[C o (N H_{3})_{6}] C l_{3}

K_{3} [F e (C N)_{6}]

K_{2} [P d (C l)_{4}]

[N i (C o)_{4}]

Q. Among the following, which complex compound is diamagnetic?

[C o (N H_{3})_{6}] C l_{3}

,
ii)

[N i (N H_{3})_{6}] C l_{2}

,
iii)

[C r (H_{2} O)_{6}] C l_{3}

,
iv)

[F e (H_{2} O)_{6}] C l_{2}

Arrange the following complexes in the increasing order of conductivity of their solution

$[C o (N H_{3})_{3} C l_{3}], [C o (N H_{3})_{4} C l_{2}] C l, [C o (N H_{3})_{6}] C l_{3}, [C o (N H_{3})_{5} C l] C l_{2}$

Q. Among the following complexes, the diamagnetic complexes are:

(K) : K_{3} [F e (C N)_{6}]

(L) : [C o (N H_{3})_{6}] C l_{3}

(M) : N a_{3} [C o (o x a l a t e)_{3}]

(N) : [N i (H_{2} O)_{6}] C l_{2}

(O) : K_{2} [P t (C N)_{4}]

(P) : [Z n (H_{2} O)_{6}] (N O_{3})_{2}

Q. The correct order of the following complexes according to increasing conductivity of their solutions will be:
(i)

[C o (N H_{3})_{3} C l_{3}]

(ii)

[C o (N H_{3})_{4} C l_{2}] C l

(iii)

[C o (N H_{3})_{6}] C l_{3}

(iv)

[C o (N H_{3})_{5} C l] C l_{2}

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