Which of the following will give $3$ -pentanone?

(C H_{3} - C H_{2} C O O)_{2} C a Δ \to

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} - C H_{2} - C | O H H - C | B r H - C H_{2} d i l . A g N O_{3} ⟶

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C H_{3} - O | | C - C H_{2} - C H_{2} - O | | C - O C_{2} H_{5} (1) H_{2} O / H^{+} ⟶ (2) N a O H (C a O)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} - C H_{2} - O | | C - C | C H_{3} H - O | | C - O H Δ \to

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $C H_{3} - C H_{2} - C | O H H - C | B r H - C H_{2} d i l . A g N O_{3} ⟶$
Only option B gives pentanone.
Hence option B is the correct answer.

Suggest Corrections

Similar questions

C H_{3} - C H = C H - C H_{2} - O | | C - C H_{3} \to C H_{3} - C H = C H - C H_{2} - O | | C - O H

C H_{2} = O H | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O H | C = C H - O | | C - C H_{3}

I

I I

I I I

C H_{2} = O H | C - C H_{2} (I) - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} (I I) - O | | C - C H_{3}

⇌ C H_{3} - O H | C = C H (I I I) - O | | C - C H_{3}

C H_{3} - O H | C H - C H_{2} - C H_{2} - O | | C - C H_{3} \to C H_{3} - O H | C H - (C H_{2})_{3} - C H_{3}

C H_{3} - C H_{3} | C H - O | | C - C H_{2} - O H | C H_{2}

Join BYJU'S Learning Program