Which of the following will give maximum number of isomer?

{[C o {(p y)}_{3} {({N H}_{3})}_{3}]}^{3 +}

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{[N i (e n) {({N H}_{3})}_{4}]}^{2 +}

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{[F e {(C_{2} O_{4})} {(e n)}_{2}]}^{2 -}

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{[C o {({N O}_{2})}_{2} {({N H}_{3})}_{4}]}^{+}

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Solution

The correct option is D ${[C o {({N O}_{2})}_{2} {({N H}_{3})}_{4}]}^{+}$
$[C o (N O_{2})_{2} (N H_{3})_{4}]^{+}$ shows the following isomerism:
1) Linkage isomerism through oxygen $[- O N O]$ and nitrogen $[- N O_{2}]$ .
2) Geometrical isomerism: 2 cis isomers and 1 trans isomer
$[N i (e n) (N H_{3})_{4}]^{2 +}$ and $[F e (C_{2} O_{4}) (e n)_{2}]^{2 -}$ will show optical isomerism. But total isomers are 4. But it has 5 isomerism.

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