Question

Which of the following will give maximum number of isomers?

• A. $\left[Co{\left(N{H}_3\right)}_{4}C{l}_2\right]$
• B. ${\left[Ni\left(en\right){\left(N{H}_3\right)}_4\right]}^{2+}$
• C. $\left[Ni\left(C_2{O}_4\right){\left(en\right)}_2\right]$
• D. ${\left[Cr{\left(SCN\right)}_2{\left(N{H}_3\right)}_4\right]}^{2+}$

Answer 1

Answer: (D)

${\left[Cr{\left(SCN\right)}_2{\left(N{H}_3\right)}_4\right]}^{2+}$

$\left[Cr\right(SCN{)}_2(N{H}_3{)}_4{]}^{2+}$ has the maximum number of isomers (geometrical + linkage). ${\left[Ni\left(en\right){\left(N{H}_3\right)}_4\right]}^{2+}$, $\left[Ni\left(C_2{O}_4\right){\left(en\right)}_2\right]$ and $\left[Co{\left(N{H}_3\right)}_{4}C{l}_2\right]$ have 2 geometrical isomers each.