Question

Which of the following will have two stereoisomeric forms?

• A. $\left[Cr{\left(N{O}_3\right)}_3{\left(N{H}_3\right)}_3\right]$
• B. $K_3\left[Fe{\left(C_2{O}_4\right)}_3\right]$
• C. ${\left[CoC{l}_2{\left(en\right)}_2\right]}^{+}$
• D. ${\left[CoBrCl{\left(Ox\right)}_2\right]}^{3-}$

Answer 1

Answer: (A), (B)

The correct options are
A $\left[Cr{\left(N{O}_3\right)}_3{\left(N{H}_3\right)}_3\right]$
B $K_3\left[Fe{\left(C_2{O}_4\right)}_3\right]$

(A) $\left[Cr{\left(N{O}_3\right)}_3{\left(N{H}_3\right)}_3\right]$ has two geometrical isomers cis and trans.

(B) $K_3\left[Fe{\left(C_2{O}_4\right)}_3\right]$ has two optical isomers d and l forms.

(C) ${\left[CoC{l}_2{\left(en\right)}_2\right]}^{+}$ has two geometrical isomers cis and trans. The cis form has two optical isomers d and l form. So has a total of four stereoisomers.

(D) ${\left[CoBrCl{\left(Ox\right)}_2\right]}^{3-}$ has two geometrical isomers cis and trans. The cis form has two optical isomers d and l form. So has a total of four stereoisomers.

Hence, the correct options are $A$ and $B$.