Question

Which of the following will not be produced when $H_{2}S$ reacts with $Mn{O}_4^{-}$ in acidic solutions?

• A. $M{n}^{2+}$
• B. $S{O}_2$
• C. $S$
• D. $H_{2}O$

Answer 1

The correct option is B $S{O}_2$

When $H_{2}S$ reacts with $Mn{O}_4^{-}$ in acidic solutions, then $H_{2}S$ is oxidized to sulphur and $M{n}^{7+}$ is reduced to $M{n}^{2+}$.
$H_{2}S\to 2H^{+}+S^{2-}5S^{2-}+2Mn{O}_4^{-}+16H^{+}\to 2M{n}^{2+}+8H_{2}O+5S$